If it's not what You are looking for type in the equation solver your own equation and let us solve it.
q in (-oo:+oo)
q*((q^2)/12) = 0
1/12*q^3 = 0 // : 1/12
q^3 = 0
q = 0
q = 0
| (a+2b)(a^2-ab+4b^2)= | | 30gi+36hi+42gi= | | -3-16=x | | 12d+9=8d+29 | | (h-1)(x+2)=2x^2-3x+5 | | 8(X-8)=17.6 | | 8(a+6)=119.2 | | -7=3c-7 | | 80+90=100 | | 5e-2=0.5 | | x^2+5x-6=2x^2-x-1 | | 9(a+1)=45 | | 9(8+1)=45 | | 9a+1=45 | | 5x-3x=7x-5 | | 2(x+7)-3x=y | | 4(a+6)=60 | | 4(a+6)=6c | | -1=2c-5 | | 1-2senx=0 | | 9a+b=a+9b | | (4-5u)(4+5u)=0 | | 9x+5=(4-x-2) | | 9x+5=4(x-2-8) | | 2t^2+2t-12=0 | | 25x^2=43 | | x+-6y=90 | | (x+5y)(x+5y)=0 | | X-(.25X)=250 | | 36x^2=7 | | a^2=49/4 | | 2ln(x+1)=5cosx |